Defining a random x

[Knittel]

But pay attention. If you want activate more than 1 of those objects by that, it may be that you activate the same object multiple times. I don't how exactly you want to use that code, but this would be the same problem, when making a program generating 6 diffrent numbers between 1 and 10. You need to pay attention that there isn't a number chosen, which was already used.

So a solution should look something like:

Code: (Select All)

NotFoundANewOne = true;

while (NotFoundANewOne) do

{

x = random(1,4);

if ("Object" + x) is already active then

NotFoundANewOne = false;

}

Set ("Object" + x) = Active

(This is NOT code for the Amnesia script, but it shows the principle of what is to be done.